Finance & Accounting

F04 · Introductory

Mathematics of Finance

9 lessons

F04 · Module 4, lesson 2 · Lesson 9 of 9

Mortgages

A home loan is an annuity with a house attached. Calculate a fixed-rate mortgage payment, compare 30- and 15-year terms, find the balance after any number of years, decide whether discount points and extra payments pay off, see what inflation does to a fixed payment, and read how an adjustable-rate mortgage resets.

About 85 minutes

Before you start

You will be able to

  • Calculate the monthly principal-and-interest payment, the total interest and the balance after k years on a fixed-rate mortgage.
  • Compare a 30-year and a 15-year mortgage on payment, total interest and how fast the balance falls.
  • Evaluate discount points by their simple break-even time and by the present value of the savings over the time the loan is kept.
  • Calculate how much time and interest regular extra payments save, using logarithms to find the new term.
  • Calculate the real value of a fixed mortgage payment under inflation, and the new payment when an adjustable-rate mortgage resets within its caps.

Review first

  • Loan amortisation — Mortgages use its payment formula, schedules and balance outstanding, and its explanation of how fees enter the APR.
  • Annuities — You need the annuity factor, solving for the number of periods with logarithms, and finding a rate by trial.
  • Inflation and real returns — You will restate fixed nominal payments in today’s dollars.

Fictional case A fictional coffee business founded by Ana Lim. It starts as a catering and barista-training service, opens its own cafés and an online shop for beans, and plans a canned cold brew.

The idea

Fictional case

March 2027. Jonah, a secondary-school teacher and an old friend of Ana’s, has agreed to buy a house for $360,000. He will pay $72,000 (20%) from his savings and borrow the other $288,000. His credit union (fictional, as are all the rates in this lesson) offers three fixed-rate loans: 30 years at 6.5%; 30 years at 6.125% if he pays 1.5 discount points upfront; or 15 years at 5.875%. Ana, who hopes to buy a flat of her own one day, is watching closely: the course project asks you to make the same kind of choice for her, with her own numbers.

A mortgage is an amortising loan

A mortgage is a loan to buy a property, secured on that property: if the borrower does not repay as agreed, the lender can take it. With a fixed-rate mortgage the interest rate never changes, so the borrower pays the same amount every month for the whole term. Each payment covers the interest due for the month and repays some principal, so the balance falls to zero by the last payment: the loan is repaid by amortisation, exactly as in the loan-amortisation lesson. The only differences are scale and length: hundreds of thousands of dollars over 180 or 360 months.

The rate is quoted per year and charged monthly, so the monthly rate is the annual rate ÷ 12. For Jonah’s 30-year offer, r=0.065÷12≈0.00541667r = 0.065 \div 12 \approx 0.00541667 and n=360n = 360 payments. The payment is the level annuity whose present value at rr equals the loan:

C=288,000×0.005416671−1.00541667−360≈$1,820.36C = 288{,}000 \times \frac{0.00541667}{1 - 1.00541667^{-360}} \approx \$1{,}820.36

In the first month the interest is 288,000×0.065÷12=1,560.00288{,}000 \times 0.065 \div 12 = 1{,}560.00 dollars, so only $260.36 of the $1,820.36 repays principal. Interest is charged on the balance, the balance starts large, and so early payments are mostly interest. As the balance shrinks, the interest part shrinks and the principal part grows; by the last payment it is almost all principal. Over 30 years Jonah would pay about $655,328.13 in total, of which about $367,328.13 is interest: more than the $288,000 he borrows.

Thirty years or fifteen

A shorter term means larger payments but far less interest, because the balance is paid down faster and there are fewer months on which to charge interest. Jonah’s credit union also charges a lower rate for the shorter term.

Jonah’s two no-points offers on $288,000 (fictional rates)
30 years at 6.5%15 years at 5.875%
Monthly payment (principal and interest)$1,820.36$2,410.90
First month: interest / principal$1,560.00 / $260.36$1,410.00 / $1,000.90
Principal repaid in the first five years$18,400.38$69,609.04
Balance after five years$269,599.62$218,390.96
Total paid over the term$655,328.13$433,962.23
Total interest$367,328.13$145,962.23

Payments are calculated without rounding and shown to the cent; totals use the unrounded payment. A lender rounds the payment to the cent and adjusts the final payment.

The 15-year loan costs $590.55 a month more but saves about $221,365.90 of interest, and after five years Jonah would owe about $51,209 less. Total interest overstates the saving, though: much of that gap is the result of repaying the loan in half the time, and each loan’s payments are worth exactly $288,000 at its own rate. The real gain is the lower rate, which is worth far less than the interest gap suggests. The 30-year loan’s advantage is flexibility: a lower required payment leaves room in the budget, and, as the theory section shows, he can still choose to pay it off faster.

Buying a lower rate: discount points

Discount points are an upfront fee paid at closing in exchange for a lower interest rate. The Consumer Financial Protection Bureau (CFPB) explains that one point costs 1% of the loan amount and that how much a point lowers the rate varies by lender, loan type and market conditions. Jonah’s 1.5 points would cost 0.015×288,000=4,3200.015 \times 288{,}000 = 4{,}320 dollars and cut his rate from 6.5% to 6.125%, which lowers the payment to about $1,749.92, a saving of about $70.44 a month.

The simple break-even time divides the cost by the monthly saving: 4,320÷70.44≈61.34{,}320 \div 70.44 \approx 61.3 months, a little over five years. If Jonah sells or refinances before then, the points lose him money; if he keeps the loan longer, they pay off. The opposite trade also exists: a lender credit lowers closing costs in exchange for a higher rate, which suits a borrower who expects to move or refinance soon.

In depth

The payment formula and the schedule

With loan PV\text{PV}, monthly rate rr and nn monthly payments, the payment is C=PV×r÷[1−(1+r)−n]C = \text{PV} \times r \div [1 - (1 + r)^{-n}]: the annuity formula of module 3 solved for the payment. Each month the interest is the opening balance times rr, the principal repaid is CC minus that interest, and the new balance is the old balance minus the principal repaid. The first three months of Jonah’s 30-year schedule:

The start of Jonah’s 30-year schedule ($288,000 at 6.5%, payment $1,820.36)
MonthInterestPrincipalBalance after payment
1$1,560.00$260.36$287,739.64
2$1,558.59$261.77$287,477.88
3$1,557.17$263.18$287,214.69
360$9.81$1,810.55$0.00

Interest = previous balance × 0.065 ÷ 12. Calculated with the unrounded payment; figures rounded to the cent.

The principal repaid grows by the factor 1 + r each month, so the balance falls slowly at first and quickly at the end. Jonah would have repaid only 6.4% of the loan after five years and 15.2% after ten; the halfway point comes in month 257, about 21 years in. The chart in “Explore” shows each year’s payments split into interest and principal.

The balance after k years

The loan-amortisation lesson gave two equivalent methods. Prospectively, the balance after kk payments is the present value of the payments still to come: Bk=C×[1−(1+r)−(n−k)]÷rB_k = C \times [1 - (1 + r)^{-(n - k)}] \div r. Retrospectively, it is what the loan would have grown to, less what the payments made would have grown to. After ten years Jonah’s 30-year balance is 1,820.36×[1−1.00541667−240]÷0.00541667≈244,155.241{,}820.36 \times [1 - 1.00541667^{-240}] \div 0.00541667 \approx 244{,}155.24 dollars. This is the figure a buyer needs when planning to sell or refinance: the sale must repay it.

Points, break-even and the APR

The simple break-even (cost ÷ monthly saving) ignores two things that pull in opposite directions. The lower rate also pays the balance down a little faster, so a seller owes slightly less; and a dollar of saving in year five is worth less than a dollar of points paid today. A sounder test values every cash flow of the points loan at the rate Jonah would otherwise pay, 6.5%. The no-points loan is worth exactly $288,000 at 6.5% for any holding period, by construction. The points loan, kept kk months and then repaid, costs:

PVpoints loan=4,320+C1×1−(1+r)−kr+Bk(1+r)k,r=0.065÷12\text{PV}_{\text{points loan}} = 4{,}320 + C_1 \times \frac{1 - (1 + r)^{-k}}{r} + \frac{B_k}{(1 + r)^k}, \qquad r = 0.065 \div 12

If that is less than $288,000, the points were worth buying. Valuing at 6.5% treats the alternative to paying points as borrowing the $4,320 at the loan rate, or using it to prepay the loan. If the cash would otherwise earn less in savings, discounting at that lower rate makes the points look better; the rate is a judgement, so state it. For Jonah it is about $614.50 more than $288,000 if he keeps the loan four years, and about $3,107.38 less if he keeps it ten. The crossover comes at about 58 months, close to the simple estimate here because the two omitted effects nearly cancel. With higher rates or a larger rate cut, they need not.

Treating the $4,320 of points as the only finance charge, the APR of Jonah’s points loan is the rate at which 360 payments of $1,749.92 are worth what he actually receives, 288,000−4,320=283,680288{,}000 - 4{,}320 = 283{,}680 dollars. By trial, or with a spreadsheet’s RATE function, that is about 6.27%, against 6.5% for the no-points loan. The APR spreads the points over the full 30 years, so it flatters points for anyone who will not keep the loan that long: kept for four years, the same loan costs about 6.56% a year. Compare APRs between loans of the same type and term, and then ask how long you will really keep the loan.

Extra payments

Prepayment, paying principal ahead of schedule, saves interest because every extra dollar stops being charged interest from that month onward. If the borrower keeps paying a fixed larger amount CC, the number of months needed solves PV=C×[1−(1+r)−n]÷r\text{PV} = C \times [1 - (1 + r)^{-n}] \div r for nn, using logarithms as in the annuities lesson:

n=−ln⁡(1−r×PV÷C)ln⁡(1+r)n = -\frac{\ln\left(1 - r \times \text{PV} \div C\right)}{\ln(1 + r)}

Adding $250 a month to Jonah’s 30-year payment, so C=2,070.36C = 2{,}070.36: r×PV÷C=1,560÷2,070.36≈0.753494r \times \text{PV} \div C = 1{,}560 \div 2{,}070.36 \approx 0.753494, and n=−ln⁡(0.246506)÷ln⁡(1.00541667)≈1.400367÷0.005402≈259.23n = -\ln(0.246506) \div \ln(1.00541667) \approx 1.400367 \div 0.005402 \approx 259.23. He would make 259 full payments and a smaller 260th, finishing in 21 years 8 months instead of 30 years. Running the schedule shows total interest of about $248,697.14, a saving of about $118,630.99.

Before planning extra payments, check the loan for a prepayment penalty. The CFPB explains that not all mortgages have one; where a loan does, it typically applies when the whole balance is paid off within a set period, usually three or five years, for example by selling or refinancing, and small extra principal payments normally do not trigger it.

A fixed payment in an inflating world

A fixed-rate mortgage payment is a fixed nominal amount: $1,820.36 in 2027 and $1,820.36 in 2056. With inflation, later payments are made in dollars that buy less. Measured in today’s dollars with the method of the previous lesson, the payment made at the end of year tt is worth C÷(1+i)tC \div (1 + i)^t. At 3% inflation (an assumption for illustration):

Jonah’s $1,820.36 payment in today’s dollars at 3% inflation
Payment made at the end of year1102030
Real value (today’s dollars)$1,767.34$1,354.52$1,007.89$749.96

1,820.36 ÷ 1.03^t, rounded to the cent. Treats each year’s payments as if made at the end of the year.

The real burden falls further if pay rises with prices. On a fictional salary of $92,000 a year, $1,820.36 is about 23.7% of Jonah’s gross monthly pay at the start; if his pay rises 3% a year, it is about 17.7% ten years later. In real terms the loan costs less than its quoted rate: the 6.5% compounded monthly is an effective annual rate of about 6.697%, a real interest rate of about 1.06697÷1.03−1≈3.59%1.06697 \div 1.03 - 1 \approx 3.59\% at 3% inflation. With a fixed rate, the lender bears the risk that inflation turns out higher than expected; the borrower bears the risk that it turns out lower.

Adjustable-rate mortgages in outline

An adjustable-rate mortgage (ARM) moves the interest-rate risk the other way. Its rate is fixed for an initial period (five years in worked example 4) and then resets at regular intervals. The CFPB explains the reset: the new rate is an index, an interest rate that moves with market conditions and that the lender chooses when you apply, plus a margin, a number of percentage points set in the loan agreement that does not change after closing. Index plus margin is called the fully indexed rate, and the actual new rate is that figure subject to the loan’s rate caps.

  • Initial adjustment cap: how far the rate can move at the first reset; the CFPB says two or five percentage points is common.
  • Subsequent adjustment cap: how far it can move at each later reset; most commonly one or two points.
  • Lifetime cap: how far it can move in total over the life of the loan; most commonly five points.

At each reset the payment is recalculated with the payment formula: the current balance, the new monthly rate and the months remaining. Worked example 4 shows the jump a borrower can face at the first reset, and why the right question about an ARM is not “what is the starting payment?” but “what is the highest payment the caps allow, and could I afford it?”

Formulas

Fixed-rate mortgage payment (principal and interest)

C=PV×r1−(1+r)−n,r=annual rate12,n=12tC = \text{PV} \times \frac{r}{1 - (1 + r)^{-n}}, \qquad r = \frac{\text{annual rate}}{12}, \quad n = 12t
CC
Monthly payment of principal and interest$ per month
PV\text{PV}
Amount borrowed: the price less the down payment$
rr
Monthly interest rate: the annual interest rate in the loan contract ÷ 12, as a decimal (not the disclosed APR, which also includes points and fees)per month
nn
Number of monthly paymentsmonths
tt
Term of the loanyears

Assumes. Payments at the end of each month; the rate is fixed for the whole term.

Property taxes, homeowners insurance and any escrow payments are extra.

Mortgage balance after k monthly payments

Bk=C×1−(1+r)−(n−k)rB_k = C \times \frac{1 - (1 + r)^{-(n - k)}}{r}
BkB_k
Balance still owed immediately after payment k$
CC
Monthly payment$ per month
rr
Monthly interest rateper month
nn
Total number of payments in the termmonths
kk
Number of payments already mademonths

The prospective balance card from the loan-amortisation lesson, with monthly periods; its retrospective card gives the same figure.

Discount points: cost and simple break-even

Cost of points=p×1%×PV,Break-even≈Cost of pointsC0−C1\text{Cost of points} = p \times 1\% \times \text{PV}, \qquad \text{Break-even} \approx \frac{\text{Cost of points}}{C_0 - C_1}
pp
Number of points bought (may be fractional)points
PV\text{PV}
Loan amount$
C0C_0
Monthly payment without points$ per month
C1C_1
Monthly payment at the lower rate$ per month
Break-even\text{Break-even}
Months of saving needed to recover the cost, ignoring time valuemonths

Assumes. Ignores the faster fall in the balance and the time value of money; the present-value test in “In depth” includes both.

How much one point lowers the rate varies by lender, loan type and market conditions.

APR with points (points as the only finance charge)

PV−F=C×1−(1+q)−nq,APR=12×q\text{PV} - F = C \times \frac{1 - (1 + q)^{-n}}{q}, \qquad \text{APR} = 12 \times q
PV\text{PV}
Loan amount$
FF
Fees paid up front: here the cost of the points, paid at closing$
CC
Monthly payment at the contract rate$ per month
qq
Monthly rate that solves the equation, found by trial or a spreadsheet RATE functionper month
nn
Number of monthly paymentsmonths
APR\text{APR}
Annual percentage rate including the pointsper year

Assumes. Points are the only finance charge beyond interest and the loan runs its full term.

The loan-amortisation lesson’s APR-with-fee card with m = 12, writing q for the solving rate to keep it apart from the contract rate r. A disclosed APR also includes broker fees and other finance charges, calculated under Regulation Z.

Months to repay with a larger payment

n=−ln⁡(1−r×PVC)ln⁡(1+r)n = -\frac{\ln\left(1 - \dfrac{r \times \text{PV}}{C}\right)}{\ln(1 + r)}
nn
Months needed to repay the balance (round up: the last payment is smaller)months
rr
Monthly interest rateper month
PV\text{PV}
Balance to be repaid$
CC
Monthly payment, including the extra amount$ per month

Assumes. The larger payment is kept up every month; no prepayment penalty applies.

Only defined when C exceeds r × PV, the first month’s interest.

Real value of a fixed payment

Real value in year t=C(1+i)t\text{Real value in year } t = \frac{C}{(1 + i)^{t}}
CC
Fixed nominal payment$
ii
Annual inflation rateper year
tt
Years from todayyears

From the previous lesson: a fixed nominal amount loses purchasing power at the inflation rate.

Adjustable-rate mortgage: the new rate

Fully indexed rate=Index+Margin;new rate within current rate±adjustment cap and initial rate±lifetime cap\text{Fully indexed rate} = \text{Index} + \text{Margin}; \quad \text{new rate within } \text{current rate} \pm \text{adjustment cap} \text{ and } \text{initial rate} \pm \text{lifetime cap}
Fully indexed rate\text{Fully indexed rate}
Index plus margin: the rate before any caps apply% per year
Index\text{Index}
A market interest rate named in the loan, which changes over time% per year
Margin\text{Margin}
Percentage points added to the index, fixed in the loan agreementpercentage points
adjustment cap\text{adjustment cap}
Most the rate can move at one reset (the initial cap at the first reset, the subsequent cap after)percentage points
lifetime cap\text{lifetime cap}
Most the rate can move over the life of the loanpercentage points
current rate\text{current rate}
The rate charged before this reset% per year
initial rate\text{initial rate}
The loan’s starting rate% per year

After each reset, recalculate C from the current balance, the new monthly rate and the months remaining. Some loans also set a floor (CFPB).

Worked examples

A first example: Jonah’s 30-year payment

Fictional figures

Jonah borrows $288,000 for 30 years at a fixed 6.5% a year, repaid monthly. Find the monthly payment of principal and interest, how the first payment splits, and the total interest over the term.

  1. Monthly rate and number of payments: r=0.065÷12≈0.00541667r = 0.065 \div 12 \approx 0.00541667; n=12×30=360n = 12 \times 30 = 360.
  2. Discount factor and annuity factor: 1.00541667−360≈0.1430251.00541667^{-360} \approx 0.143025, so [1−0.143025]÷0.00541667≈158.2108[1 - 0.143025] \div 0.00541667 \approx 158.2108.
  3. Payment: C=288,000÷158.2108≈1,820.36C = 288{,}000 \div 158.2108 \approx 1{,}820.36 dollars.
  4. First month: interest 288,000×0.00541667=1,560.00288{,}000 \times 0.00541667 = 1{,}560.00; principal 1,820.36−1,560.00=260.361{,}820.36 - 1{,}560.00 = 260.36; new balance $287,739.64.
  5. Total interest: 360×1,820.3559−288,000≈367,328.13360 \times 1{,}820.3559 - 288{,}000 \approx 367{,}328.13 dollars (using the unrounded payment).

Answer. A payment of about $1,820.36 a month; the first payment is $1,560.00 of interest and $260.36 of principal; total interest about $367,328.13.

What it means. Jonah would pay back about 2.28 times what he borrows. The early payments barely dent the balance, which is why the balance after a few years, not the original loan, is what matters if he sells or refinances.

A harder example: Are 1.5 points worth $4,320?

Fictional figures

Jonah can cut his 30-year rate from 6.5% to 6.125% by paying 1.5 points on $288,000. Find the cost, the monthly saving and the simple break-even, then test the decision properly for a four-year and a ten-year stay by valuing the points loan’s cash flows at 6.5%.

  1. Cost: 1.5×1%×288,000=4,3201.5 \times 1\% \times 288{,}000 = 4{,}320 dollars. New payment at 0.06125÷120.06125 \div 12 over 360 months: about $1,749.92, against $1,820.36. Saving about $70.44 a month.
  2. Simple break-even: 4,320÷70.44≈61.34{,}320 \div 70.44 \approx 61.3 months, about 5 years 1 month.
  3. Four-year stay. Balance on the points loan after 48 payments: about $272,818.58. At r=0.065÷12r = 0.065 \div 12, the 48-month annuity factor is about 42.167488 and the discount factor 1.00541667−48≈0.771592771.00541667^{-48} \approx 0.77159277. Value of the points loan, with the unrounded payment of $1,749.9184: 4,320+1,749.9184×42.167488+272,818.58×0.77159277≈288,614.504{,}320 + 1{,}749.9184 \times 42.167488 + 272{,}818.58 \times 0.77159277 \approx 288{,}614.50 (calculated with unrounded figures), which is $614.50 more than the $288,000 the no-points loan is worth.
  4. Ten-year stay. Balance after 120 payments about $241,814.64; annuity factor about 88.0685; discount factor about 0.52296229. Value: 4,320+1,749.9184×88.0685+241,814.64×0.52296229≈284,892.624{,}320 + 1{,}749.9184 \times 88.0685 + 241{,}814.64 \times 0.52296229 \approx 284{,}892.62 (unrounded figures), about $3,107.38 less than $288,000.
  5. Crossover: repeating the test month by month, the points start to pay off from about month 58.

Answer. The points cost $4,320 and save about $70.44 a month: a simple break-even of about 61 months. In present-value terms they lose about $614.50 if Jonah keeps the loan four years and gain about $3,107.38 if he keeps it ten; the crossover is about 58 months.

What it means. Points are a bet on staying put. Jonah should buy them only if he is fairly confident of keeping this loan for well over five years, with no sale or refinancing in between. If rates might fall, so that refinancing becomes attractive, the case for points weakens.

Applied: a business decision: A 15-year loan, or a 30-year loan paid faster?

Fictional figures

Jonah earns a fictional $92,000 a year. He likes the idea of being debt-free sooner but worries about committing to $2,410.90 a month. Compare (a) the 15-year loan at 5.875%, (b) the 30-year loan at 6.5% with $250 a month extra, and (c) the 30-year loan paid at the 15-year payment of $2,410.90 by choice.

  1. Required payments as a share of gross monthly pay ($92,000 ÷ 12 ≈ $7,666.67): 15-year $2,410.90, about 31.4%; 30-year $1,820.36, about 23.7%.
  2. (b) With $250 extra, C=2,070.36C = 2{,}070.36. Months: n=−ln⁡(1−1,560÷2,070.36)÷ln⁡(1.00541667)≈259.23n = -\ln(1 - 1{,}560 \div 2{,}070.36) \div \ln(1.00541667) \approx 259.23, so 260 payments, about 21 years 8 months. Total interest by the schedule about $248,697.14, saving about $118,630.99 against the scheduled 30 years.
  3. Paying $2,410.90 a month on the 30-year loan clears it in 193 months with total interest of about $176,798.18, against about $145,962.23 on the 15-year loan.
  4. The difference, about $30,835.95, is what the 15-year loan’s lower rate is worth if Jonah would really pay that much every month; it is the price of keeping the right to pay less in a bad month.

Answer. The 15-year loan is cheapest (interest about $145,962.23) if Jonah can always pay $2,410.90. Paying the 30-year loan at the same amount costs about $30,835.95 more in interest but keeps a required payment of only $1,820.36; $250 extra a month clears it in about 21 years 8 months and saves about $118,630.99.

What it means. Commitment is cheaper; flexibility has a price. A borrower with a secure income and a full emergency fund should lean to the 15-year loan; one whose income may dip, or who wants to keep cash for other goals, may rationally pay more interest for the 30-year loan and prepay when he can, after checking that the loan has no prepayment penalty.

A harder example: An adjustable-rate mortgage resets

Fictional figures

Instead, Jonah is offered a fictional ARM on $288,000: 5.75% fixed for five years, then resetting once a year to an index plus a 2.75-point margin, amortised over 30 years. Caps: 2 points at the first reset, 1 point at each later reset, 5 points over the life of the loan. At the first reset the index is 4.5%. Find the payment before and after the reset, and the most the rate could ever reach.

  1. Starting payment at 0.0575÷120.0575 \div 12 over 360 months: about $1,680.69, which is $139.67 less than the fixed 6.5% loan.
  2. Balance after 60 payments (prospective method at the starting rate): 1,680.69×[1−1.00479167−300]÷0.00479167≈267,155.101{,}680.69 \times [1 - 1.00479167^{-300}] \div 0.00479167 \approx 267{,}155.10.
  3. New rate: fully indexed 4.5%+2.75%=7.25%4.5\% + 2.75\% = 7.25\%; the first-reset cap allows up to 5.75%+2%=7.75%5.75\% + 2\% = 7.75\%, so the rate becomes 7.25%.
  4. New payment: $267,155.10 over the remaining 300 months at 0.0725÷120.0725 \div 12 gives about $1,931.02, a rise of about $250.33 (14.9%).
  5. Worst cases: had the index been above 5.0%, the cap would have held the rate at 7.75% and the payment at about $2,017.90. Over the life of the loan the rate can never exceed 5.75%+5%=10.75%5.75\% + 5\% = 10.75\%.

Answer. About $1,680.69 a month for five years, then about $1,931.02 at 7.25%; the cap limits the first reset to 7.75% (about $2,017.90), and the rate can never exceed 10.75%.

What it means. The ARM was cheaper for five years and dearer afterwards in this scenario. It suits a borrower who expects to sell or refinance before the first reset, or who could absorb the capped worst-case payment; it does not suit one who chose it only because the starting payment was lower.

Explore

Start with Jonah’s loan. Shorten the term, change the rate, add an extra monthly payment and watch the balance line fall faster; the rows show the months and interest saved and what the final scheduled payment is worth after inflation.

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Points against holding period. Change the number of points, how much each one cuts the rate, and how long you keep the loan. Compare the simple break-even with the present-value test, and find the holding period at which buying points stops making sense.

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Each year’s twelve payments on Jonah’s 30-year loan, split into interest and principal. The total is the same every year; only the split changes.

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Common mistakes

  • Using the annual rate with monthly payments

    The payment uses the monthly rate (annual ÷ 12) and the number of months (12 × years). Using 6.5% with 360 periods gives about $18,720 a month, which is absurd; working out an annual payment over 30 years and dividing by 12 gives about $1,837.86, which looks plausible but is still wrong, because interest is charged monthly.

  • Treating the payment as the whole housing cost

    The formula covers principal and interest only. Property taxes and homeowners insurance, often collected through escrow, come on top and can change every year.

  • Judging points by the APR alone

    The APR spreads points over the full term. If you will sell or refinance in a few years, the cost of the loan over the time you actually keep it can be higher than the no-points loan, even though its APR is lower.

  • Thinking the balance falls evenly

    After a third of the term, Jonah would have repaid less than a sixth of the loan. Interest dominates early payments; find the balance with the balance formula, not by subtracting payments.

  • Comparing an ARM’s starting payment with a fixed payment

    The starting payment lasts only for the fixed period. Compare the fixed payment with the payment the caps allow after resets, and plan for the worst case.

  • Forgetting inflation when judging a 30-year commitment

    A fixed payment of $1,820.36 is worth about $750 in today’s dollars by year 30 at 3% inflation. The real burden falls over time, though only inflation that turns out higher than expected helps the borrower beyond what the rate already allowed for.

Guided practice

Work through these with hints when you need them. Every hint and every worked solution is there to be used.

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On your own

No hints this time. Answer, check, and read the feedback; the solution appears once you have answered or if you ask for it. Your first answers count toward mastery.

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In practice

Fictional case

Jonah takes the 30-year fixed loan without points. He expects to stay in the house for many years, but his school may relocate him within five, and the simple and present-value break-evens both say he would need to stay about five years for points to pay. He sets up an automatic extra $250 a month, after confirming with the credit union that the loan has no prepayment penalty, and keeps the option to stop if his budget tightens. Ana notes the method: in the project you will run the same comparison for her, with her own loan, rates and points offer.

Comparing Loan Estimates. A loan officer at a fictional credit union helps a nurse compare three quotes received the same week for the same loan type and term. She lines up the interest rates on page 1, the points and fees on page 2 and the APRs on page 3, then asks the question the APR cannot answer: how long will you keep this loan? For a buyer likely to move within four years she points out the no-points or lender-credit options; for one planning to stay fifteen years, the points option.

Preparing for an ARM reset. A housing counsellor meets a fictional couple whose five-year ARM resets in six months. She finds their current balance, the index level and the margin from their loan documents, computes the payment at the fully indexed rate and at the cap, and compares both with their budget. If the capped payment would strain them, she sets out the alternatives early: refinancing to a fixed rate, making extra payments now to reduce the balance, or adjusting the budget.

A business buying its premises. The owner of a fictional dental practice compares renting with buying a small building financed by a commercial mortgage. The same arithmetic applies: the payment formula, the balance after the years she expects to stay, and the present value of the costs of each option at her required return. Because the mortgage payment is fixed while her rent would rise with an escalation clause, she makes the comparison in real terms, as in the previous lesson.

Knowledge check

Six questions, one attempt each, no hints. Score 80% or more to complete the lesson; you can take it again at any time.

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Summary

  • A fixed-rate mortgage is an amortising loan: C = PV × r ÷ [1 − (1 + r)^−n] with r = annual rate ÷ 12 and n = months. Taxes, insurance and escrow are extra.
  • Early payments are mostly interest; the balance after k payments is the present value of the remaining payments.
  • A 15-year loan has higher payments and far less total interest than a 30-year loan; a 30-year loan with voluntary extra payments buys flexibility at a price.
  • One discount point costs 1% of the loan. Simple break-even = cost ÷ monthly saving; the sounder test values the points loan’s cash flows over the expected holding period.
  • The disclosed mortgage APR includes points and other finance charges but assumes the loan runs its full term.
  • Extra payments shorten the term: n = −ln(1 − rPV ÷ C) ÷ ln(1 + r). Check for a prepayment penalty first.
  • Inflation reduces the real value of a fixed payment: C ÷ (1 + i)^t.
  • An ARM resets to index + margin within initial, subsequent and lifetime caps; judge it by the capped worst-case payment.

Key formulas

Terms introduced

Mortgage
A loan to buy a property that is secured on that property, so the lender can take the property if the borrower does not repay as agreed.
Fixed-rate mortgage
A mortgage whose interest rate stays the same for the whole term, so the monthly payment of principal and interest never changes.
Down payment
The part of a property’s price that the buyer pays from their own funds; the mortgage finances the rest.
Discount points
Fees paid to a lender at closing in exchange for a lower interest rate; one point costs 1% of the loan amount. Often called points.
Lender credit
Money a lender contributes to a borrower’s closing costs in exchange for a higher interest rate: the opposite of discount points.
Escrow account
An account set up by a mortgage lender and funded from part of each monthly payment, from which property taxes and homeowners insurance are paid. Also called an impound account.
Adjustable-rate mortgage
A mortgage whose interest rate is fixed for an initial period and then resets at intervals to an index plus a margin, within rate caps. Often shortened to ARM.
Fully indexed rate
For an adjustable-rate mortgage, the index plus the margin: the rate the loan would reset to before any caps apply.
Rate cap
A limit on how much an adjustable rate can change at the first reset, at each later reset, or in total over the life of the loan.

Sources

  1. Consumer Financial Protection Bureau. What are (discount) points and lender credits and how do they work? consumerfinance.gov/ask-cfpb/what-are-discount-points-and-le…
  2. Consumer Financial Protection Bureau. What is the difference between a mortgage interest rate and an APR? Last reviewed 28 August 2026. consumerfinance.gov/ask-cfpb/what-is-the-difference-between-…
  3. Consumer Financial Protection Bureau. Regulation Z (Truth in Lending), 12 CFR §1026.4: Finance charge. consumerfinance.gov/rules-policy/regulations/1026/4
  4. Consumer Financial Protection Bureau. What is an escrow or impound account? consumerfinance.gov/ask-cfpb/what-is-an-escrow-or-impound-ac…
  5. Consumer Financial Protection Bureau. What is a prepayment penalty? consumerfinance.gov/ask-cfpb/what-is-a-prepayment-penalty-en…
  6. Consumer Financial Protection Bureau. For an adjustable-rate mortgage (ARM), what are the index and margin, and how do they work? consumerfinance.gov/ask-cfpb/for-an-adjustable-rate-mortgage…
  7. Consumer Financial Protection Bureau. With an adjustable-rate mortgage (ARM), what are rate caps and how do they work? Last reviewed 14 January 2025. consumerfinance.gov/ask-cfpb/with-an-adjustable-rate-mortgag…